[LeetCode 58] Length of Last Word

Question

link

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = "Hello World",
return 5.

Stats

Frequency	1
Difficulty	1
Adjusted Difficulty	1
Time to use	--------

Ratings/Color = 1(white) 2(lime) 3(yellow) 4/5(red)

Solution

This is a easy question.

My code

public class Solution {
    public int lengthOfLastWord(String s) {
        if (s == null || s.length() == 0) {
            return 0;
        }
        int p = s.length() - 1;
        while (p >= 0 && s.charAt(p) == ' ') {
            p--;
        }
        if (p == -1) {
            return 0;
        }
        int q = p;
        while (q >= 0 && s.charAt(q) != ' ') {
            q--;
        }
        return p - q;
    }
}