Link: https://leetcode.cn/problems/count-complete-tree-nodes/
Question
difficulty: mid
adj diff: 3
Given the root of a complete binary tree, return the number of the nodes in the tree.
According to Wikipedia, every level, except possibly the last, is completely filled in a complete binary tree, and all nodes in the last level are as far left as possible. It can have between 1 and 2h nodes inclusive at the last level h.
Design an algorithm that runs in less than O(n) time complexity.
Example 1:
Input: root = [1,2,3,4,5,6]
Output: 6
Example 2:
Input: root = []
Output: 0
Example 3:
Input: root = [1]
Output: 1
Constraints:
The number of nodes in the tree is in the range [0, 5 * 104].
0 <= Node.val <= 5 * 104
The tree is guaranteed to be complete.
判断左右 depth,是否相等。
Code
public int countNodes(TreeNode root) {
if (root == null) return 0;
int depthLeft = depth(root.left);
int depthRight = depth(root.right);
if (depthLeft == depthRight) {
// left tree is complete
return (int) Math.pow(2, depthLeft) + countNodes(root.right);
} else {
return 1 + countNodes(root.left) + countNodes(root.right);
}
}
private int depth(TreeNode node) {
if (node == null) return 0;
return depth(node.left) + 1;
}