Link: https://leetcode.cn/problems/product-of-array-except-self/
Question
difficulty: mid
adj diff: 3
Given an integer array nums, return an array answer such that answer[i] is equal to the product of all the elements of nums except nums[i].
The product of any prefix or suffix of nums is guaranteed to fit in a 32-bit integer.
You must write an algorithm that runs in O(n) time and without using the division operation.
Example 1:
Input: nums = [1,2,3,4]
Output: [24,12,8,6]
Example 2:
Input: nums = [-1,1,0,-3,3]
Output: [0,0,9,0,0]
Constraints:
2 <= nums.length <= 105
-30 <= nums[i] <= 30
The product of any prefix or suffix of nums is guaranteed to fit in a 32-bit integer.
Follow up: Can you solve the problem in O(1) extra space complexity? (The output array does not count as extra space for space complexity analysis.)
左右,乘 2 次就行了。
Code
public int[] productExceptSelf(int[] nums) {
int len = nums.length;
int[] ans = new int[len];
ans[0] = 1;
int temp = 1;
for (int i = 1; i < len; i++) {
// Input: [1, 2, 3, 4]
// ans : [1, 1, 2, 6]
temp *= nums[i - 1];
ans[i] = temp;
}
temp = 1;
for (int i = len - 2; i >= 0; i--) {
// Input:= [ 1, 2 , 3, 4]
// Output: [24, 12, 8, 6]
temp *= nums[i + 1];
ans[i] *= temp;
}
return ans;
}